If it's not what You are looking for type in the equation solver your own equation and let us solve it.
10x^2+x-24=0
a = 10; b = 1; c = -24;
Δ = b2-4ac
Δ = 12-4·10·(-24)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-31}{2*10}=\frac{-32}{20} =-1+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+31}{2*10}=\frac{30}{20} =1+1/2 $
| 643=4*106+n | | 2(w+4)=7w-37 | | (2x-9)*(3x+2)=x | | 32=c+1/4 | | v−54=2 | | x-3/2(4)=-2 | | 16+5a=8(8a+2) | | 85+64+x=180 | | -4d+8=-3d | | p*34=7.48 | | 2z+⅜=3⅞ | | 34-2x=71 | | 5^x=125^7 | | 11j+-10j+-2=-12 | | 5.5x-3.4+8.5x=442 | | 7x+8+11=12x+7 | | 5.5n-3.4+8.5n=442 | | 17u+4u+6=-15 | | -1+2(-1-3x)=-11-5x | | 5(11+2^2-10)-19=x | | 2j=3j-9 | | 2-x+4=1/10x+1/10 | | 5x-4(x-6=-11 | | 3p2+10p-8=0 | | 0.5x+0.2(30)=46.5 | | 4x-2=2+40 | | -6+10s=9s | | 35+(5z-2)+2z=180 | | a/12=15 | | n-20=30 | | -14=1-z | | -132=-4+4(8b+8) |